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Segment And Angle Addition Postulate

Segment addition postulate

The segment add-on postulate states the following for three points that are collinear.


Consider the segment on the correct.

collinear points


If 3 points A, B, and C are collinear and B is between A and C, then

AB + BC = Air-conditioning

Using the segment addition postulate to solve a problem.

Segment addition postulate

Suppose AC =  48, detect the value of ten. So, find the length of AB and the length of BC.

AB + BC = Air-conditioning

( 2x - iv ) + ( 3x + 2 ) = 48

2x + 3x - 4 + 2 = 48

5x - 4 + 2 = 48

Add 4 to both sides of the equation.

5x - 4 + 4 + two = 48 + iv

5x + 2 = 52

Subtract 2 from both sides.

5x + 2 - two = 52 - ii

5x = fifty

Dissever both sides by v

5x / 5 = 50 / v

x = 10

Now that we have the value of x, we can notice the length of AB and the length of BC.

AB = 2x - 4

AB = ii × 10 - 4

AB = 20 - 4 = sixteen

The length of AB is xvi

BC = 3x + ii

BC = 3 × x + 2

BC = 30 + 2 = 32

The length of BC is 32.


Segment addition postulate and the midpoint

Suppose XA = 3x and AY =  4x - 6. If A is the midpoint of XY, what is the length of XY?

           3x                       4x - half dozen
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Ten                         A                         Y

The fob in this problem is to see that if A is the midpoint, then XA = AY.

Since XA = AY, 3x = 4x - 6

Subtract 3x from both sides.

3x - 3x = 4x - 3x - 6

0  = x - 6

Add 6 to both sides of the equation.

0 + six = ten - vi + 6

half dozen = x

To compute XA, y'all can either use 3x or 4x - six

Using 3x, nosotros get XA = AY = 3 × 6 = 16

Using 4x - 6, we get XA = AY = iii × vi - half dozen = 18 - half dozen = 12

XY = XA + AY = 16 + 16 = 32

The length of XY is 32.

Segment And Angle Addition Postulate,

Source: https://www.basic-mathematics.com/segment-addition-postulate.html

Posted by: jewellcracenduch.blogspot.com

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